VTU Civil Engineering (Semester 5)
Transport Engineering 1
June 2015
Total marks: --
Total time: --
INSTRUCTIONS
(1) Assume appropriate data and state your reasons
(2) Marks are given to the right of every question
(3) Draw neat diagrams wherever necessary


1 (a) What are the social effects of transportation?
6 M
1 (b) What are the advantages and disadvantages of airways?
6 M
1 (c) What are the objectives of IRC and Central Roads Research Institute?
8 M

2 (a) With sketches indicate different road patterns.
6 M
2 (b) Indicate the details to be collected in: i) Traffic surveys ii) Engineering surveys, While planning a highway.
6 M
2 (c) The area of district is 8400km3, There are 9 towns with population greater than 5000. Calculate the length of NH, SH, MDR, ODR+VR as par 3rd 20 year road plan.
8 M

3 (a) Briefly explain how map study is helpful in the alignment of new highway.
6 M
3 (b) The width of pavement is 7.5m and parabolic camber of 1 in 40 is to provided. Design the parabolic profile of the pavement surface.
6 M
3 (c) A vehicle is moving at 55kmph on a single lane pavement of width 4mts on level surface. The reaction time is 2.3 secs and coefficient of longitudinal friction is 0.39. Determine the intermediate sight distance.
8 M

4 (a) Design the length of transition curve for a speed of 65 kmph on a 2-lane highway with a width of 7.0 mts. The radius of the curve o the curve is 220mts. The super elevation is provided by raising the outer edge with respect to inner edge. The rate of raising the outer edge is 1 in 150 in open country. The wheel base is 6.1 mts.
12 M
4 (b) An up gradient of 1 in 18 meets another up-gradient of 1 in 48. Design the length of the vertical curve to be provided for a SSD of 70 mts. Mention the type of curve provided.
8 M

5 (a) The CBR test results are as follows:
Apply correction and determine the CBR value of the soil.
Load in kgs 0 2 4 9 20 34 49 74 92 118 125
Penetration in mm 0 0.5 1 1.5 2 2.5 3 4 5 7.5 10
8 M
5 (b) The result of soil test is as follows:
Determine the Group Index and classify the soil as per HRB system. Discuss its suitability as subgrade material.
Sieve size 0.074 mm % age passing is 45%
Liquid Limit 38 %
Plastic Limit 27 %
8 M
5 (c) Define cut back bitumen. What is SC, MC and RC cutback bitumen?
4 M

6 (a) Design the bituminous pavement with the following data:
4-lane divided carriageway.
Traffic in each direction= 5600 CVD; Design life=9 yrs; CBR=5%;
Traffic growth rate= 8%; Vehicle damage factor = 4.5; Distribution factor = 0.75. Indicate pavement composition. Also, after 4 years determine the thickness of DBM and BC to be laid.
10 M
6 (b) Determine warping stress at interior, edge and corner region for the following data.
Slab thickness= 25 cm; Slab size=3.6×11m; Modulus of subgrade reaction=6.9 kg/cm3; Temperature differential = 0.6°C per cm; Radius of area of contact, a=15 cm; e=10×10-6/°C; E=3×105 kg/cm2; μ=0.15.
10 M

7 (a) Mention the specification of materials and construction procedure for Wet Mix Macadam.
8 M
7 (b) What are the requirement of highway drainage system?
4 M
7 (c) The sieve analysis of subgrade soil is as follows:
Size of perforation in drain pipe=2.5mm. Design the filter material for
i) Permeability condition ii) Prevent piping condition.
Sieve size mm 4 2 1  600μmm   300μmm   150μm   75μm 
% age passing 100 88 70 52 25 10 5
8 M

8 (a) Mention factors affecting vehicle operation cost dependent on time.
4 M
8 (b) Analyse the economics by Benefit - Cost Ratio method for proposal A, B and C.
  A B C
Highway cost  1,  76, 527  3,  81, 900   3,  75, 100,
Road user cost  32, 57, 857 28, 73, 025  27, 52, 345
6 M
8 (c) Calculate the Annual cost a stretch of highway
Particulars Cost in lakhs Life in years Rate of S. int %
Right of way 140 100 7
Earth work 90 40 8
Bridges 85 70 8
Pavement 160 12 9

Maintenance cost is Rs 12 lakh per year.

Take 1: Pavement design catalogue for traffic range 10-150 msa
CBR 5%
Cumulative Traffic msa Total Pavement
thickness mm
Pavement composition
Bituminous surface Granular base and sub base mm
BCmm DBMmm
10 660 40 70 Base= 250

SubBase=300


 
20 690 40 100
30 710 40 120
50 730 40 140
100 750 50 150
150 770 50 170

Table 2: Values of coefficient C
Lx/l or Ly/l 1 2 3 4 5 6 7 8 9 10 11 12 & >12
Cx or Cy 0 0.04 0.175 0.44 0.72 0.92 1.03 1.075 1.08 1.075 1.05 1.03
10 M



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