Explain the following terms:

1 (a) (i)
Face left and face right observations.

2 M

1 (a) (ii)
Transit and non-transit theodolites

2 M

1 (b)
With neat sketch and tabular column explain measurement of horizontal angle by reiteration method.

10 M

1 (c)
With neat sketch explain prolonging a straight line by a theodolite in adjustment and theodolite not in adjustment.

6 M

2 (a)
What is spire test? With neat sketch, explain bow it is carried.

10 M

2 (b)
A dumpy level was set up at L

_{1}exactly midway between A and B which are 50m apart. The readings on the staff when held on A and B were respectively 2.40m and 1.40m. The instrument was then shifted and set up-at point L_{2}on the line AB produced at 10m from A. The readings on the staff held at A and B were respectively 2.5m and 1.40m. Determine the staff readings on A and B to given a horizontal line of sight. Determine the R.L. of B, if that of A is 200.0m.
10 M

3 (a)
What is a total station? List out the advantages of total station.

6 M

3 (b)
To find the elevation of the top of a hill, a flag staff of 4m height was erected with its top at Q. Observations were made from two stations M and N, 60m apart and not in line with Q. The angles of elevation to the top of the flag staff from stations M and N were measured as 10°50' and 11°28' respectively. The horizontal angle measured at M between N and the top of the flag staff was 56°30' and the measured at N between M and the top of the flag post was 62°10'.

If the reading on B.M. with an elevation of 400.0m when the instrument was at M and the line of sight was horizontal is 1.785m, determine the elevation of the top of the hill. If the staff readings on the B.M. When the instrument was at N, was 1.794m determine the elevation of the top of the flag hill and compare with the earlier computed value.

If the reading on B.M. with an elevation of 400.0m when the instrument was at M and the line of sight was horizontal is 1.785m, determine the elevation of the top of the hill. If the staff readings on the B.M. When the instrument was at N, was 1.794m determine the elevation of the top of the flag hill and compare with the earlier computed value.

14 M

4 (a)
Derive the expression for distance and elevation when the staff is held vertical and the line of sight is inclined.

8 M

4 (b)
A tacheometer was set up at station A and the following readings were obtained on vertically held staff:

Calculate the horizontal distance fro A and B and the R.L. of B if the constant of the instrument were K=100 and C=0.4

Calculate the horizontal distance fro A and B and the R.L. of B if the constant of the instrument were K=100 and C=0.4

Station |
Staff Station |
Vertical angle |
Cross-hair readings in m |
Remarks |

A | B.M. | -2°18' | 3.225, 3.55, 3.875 | RL of B.M.=437.655 m |

B | +8°36' | 1.650, 2.515, 3.380 |

12 M

5 (a)
With neat sketches, explain different types of curves.

6 M

5 (b)
What do you mean by degree of curve? Derive the relation between degree and radius of simple curve based on chord definition.

5 M

5 (c)
Two tangents intersect at chainage 59-60, the deflection angle being 50&Deg;30'. Calculate the necessary data for setting out a curve of 15 chains radius to connect the two tangents if it is intended to set out the curve by offset from chord produced. Take peg interval equal to 100 links, length of chain being equal to 20m (100 links).

9 M

6 (a)
The following data refer to a compound curve which bears to the right.

Total deflection angle 93°

Degree of first curve=4°

Degree of second curve=5°

Point intersection at 45+61 (20m units). Determine in 20 units the running distance of the tangent points and the point of compound curvature, given that the latter point is 6+24 from the point of intersection at a back angle of 290°36' from the first tangent.

Total deflection angle 93°

Degree of first curve=4°

Degree of second curve=5°

Point intersection at 45+61 (20m units). Determine in 20 units the running distance of the tangent points and the point of compound curvature, given that the latter point is 6+24 from the point of intersection at a back angle of 290°36' from the first tangent.

10 M

6 (b)
Two straight AB and CD intersect at V. BD is the common tangent of length 200m. It is proposed to introduce a reverse curve consisting of two ares of equal radii between them. The angles ABD and CDB are 150°30' and 43°42' respectively. Calculate:

i) The common radius;

ii) The chainages of P.C., P.R.C. and P.T. if that of B is 9245.2m.

i) The common radius;

ii) The chainages of P.C., P.R.C. and P.T. if that of B is 9245.2m.

10 M

7 (a)
What is a transition curve? Discuss the purpose of introducing transition curve between a straight and a simple curve.

6 M

7 (b)
What is vertical curve? With sketch briefly explain different types of vertical curves.

5 M

7 (c)
A transition curve is required for a circular curve of 200m radius the gauge being 1.5m and maximum super elevation restricted to 15cm. The transition is to be designed for a velocity such that no lateral pressure is imposed on the rails and the rate of gain of radial acceleration is 30cm/sec

^{3}, calculate the required length of the transition curve and the design speed.
9 M

8 (a)
Plot the following cross-staff survey of a field ABCDEFG and calculate its areas. Refer Fig. Q8 (a)

5 M

8 (b)
The following observations were made with a planimeter.

The anchor point was placed outside the figure in both the case with the same setting of the tracing arm. Calculate: i) the multiplier constant ii) The unknown area.

The following areas within the contour lines at the site of a reservoir and face of the proposal dam are as follows:

Assuming 100m as the bottom level of the reservoir and 118 m as the water level, calculate the volume (capacity) of water that can be stored in the reservoir. Use trapezoidal and prismoidal formula.

SI. No |
Area |
I.R. |
F.R. |
N |

1 | known area of 60 cm2 | 2.326 | 8.286 | 0 |

2 | Unknown area | 8.286 | 5.220 | -1 |

The anchor point was placed outside the figure in both the case with the same setting of the tracing arm. Calculate: i) the multiplier constant ii) The unknown area.

The following areas within the contour lines at the site of a reservoir and face of the proposal dam are as follows:

Contour |
Area enclosed in sqm |

100m | 1000 |

103m | 12800 |

106m | 16600 |

109m | 18800 |

112m | 24400 |

115m | 30600 |

118m | 38400 |

Assuming 100m as the bottom level of the reservoir and 118 m as the water level, calculate the volume (capacity) of water that can be stored in the reservoir. Use trapezoidal and prismoidal formula.

10 M

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