STUPIDSID
1(a)
With block diagram explain a Mechatronics Design process.
5 M
1(b)
Explain Inertia matching with a sketch.
5 M
1(c)
Explain procedure for selection of actuator.
5 M
1(d)
Explain procedure for Cantilever beam vibration control using piezo sensors.
5 M
1(e)
Draw properly labeled sketch of a torque development process in three phase motor and explain.
5 M
2(a)
Explain heat dissipation in DC motor and Derive an equation for thermal modeling of DC motor.
10 M
2(b)
Explain Piezoelectric drives with neat sketch. State its applications.
10 M
3(a)
Two double acting pneumatic cylinders A, B are selected for an industrial application. The sequence of movement for cylinder is as indicated below-
(AB)+Delav (5sec) (AB)- Draw the electropneumatic circuit using 5/2 double solenoid as final directional control valves.
(AB)+Delav (5sec) (AB)- Draw the electropneumatic circuit using 5/2 double solenoid as final directional control valves.
10 M
3(b)
Explain with diagram procedure for interfacing motor drive with microcomputer system.
10 M
4(a)
Explain Stepper motor performance charateristics with neat sketch.
10 M
4(b)
Explain with a block diagram Multichannel Data Acquisition systems (DAQs). State its benefits
10 M
5(a)
Write PLC ladder logic diagram as per the operational sequence given below figure.
!mage An explanation of the operational sequence is as follows:
Step1:The sequence begins by pressing the start button I: l in rung 0. As output 0.2/0 becomes energized, the rung becomes latched and corresponding contacts in rungs l. 3. 5. 6. and 9 close. The system becomes de-energized by pressing the stop button l: 1/0 in rung 0.
Step2:The closure of the start button also causes rung l to latch. By energizing output 0:2/l in rung 1. both conveyor belts begin running. When an empty can from the input conveyor enters the slot in position 1. it activates a limit switch that turns rung 2 True. As the output of rung 2 energizes, it Creates a False condition at Examine- Off contact 0:2/2, rung 1 unlatches, and the conveyor belts stop. Rung 3 is now in the True condition.
Step 3: When rung 3 becomes True. its output causes a valve to open and paint pours into an empty can at position 9. As the paint fills the can, a strain gauge measures the weight and sends a voltage, which is proportional to the weight of the paint, to an analog-to-digital module in the PLC The A/D converter module produces a proportional digital value at address 1:6.0. This digital value is compared using the EQU instruction on rung 4. Source A of the EQU instruction is the weight of the paint and source B is the program constant of 128.
Step4:When the paint can fills to I28 ounces, the values at source A and source B of the EQU instruction are the same. which energizes the rung and turns on B3/0 The corresponding Examine-Off (B3/0) on rung 3 becomes False and shuts off the valve. Also. the B3/0 contact on rung 6 energizes the rung. causing a robotic arm to place a lid on the can. When sensor 1: l/4 in rung 6 detects the placement of the lid. it causes the rung to latch, starting a motor that rotates the table.
Step5: As the table and incremental encoder rotate, the tip-counter C5:0 in rung 8 increments. Alter 72 pulses, the accumulator equals the preset value. The DN output of the counter then sets. causing the corresponding Examine-Off contact in rung 6 to become False. The result is that the rung unlatches and the rotary motor stops.
!mage An explanation of the operational sequence is as follows:
Step1:The sequence begins by pressing the start button I: l in rung 0. As output 0.2/0 becomes energized, the rung becomes latched and corresponding contacts in rungs l. 3. 5. 6. and 9 close. The system becomes de-energized by pressing the stop button l: 1/0 in rung 0.
Step2:The closure of the start button also causes rung l to latch. By energizing output 0:2/l in rung 1. both conveyor belts begin running. When an empty can from the input conveyor enters the slot in position 1. it activates a limit switch that turns rung 2 True. As the output of rung 2 energizes, it Creates a False condition at Examine- Off contact 0:2/2, rung 1 unlatches, and the conveyor belts stop. Rung 3 is now in the True condition.
Step 3: When rung 3 becomes True. its output causes a valve to open and paint pours into an empty can at position 9. As the paint fills the can, a strain gauge measures the weight and sends a voltage, which is proportional to the weight of the paint, to an analog-to-digital module in the PLC The A/D converter module produces a proportional digital value at address 1:6.0. This digital value is compared using the EQU instruction on rung 4. Source A of the EQU instruction is the weight of the paint and source B is the program constant of 128.
Step4:When the paint can fills to I28 ounces, the values at source A and source B of the EQU instruction are the same. which energizes the rung and turns on B3/0 The corresponding Examine-Off (B3/0) on rung 3 becomes False and shuts off the valve. Also. the B3/0 contact on rung 6 energizes the rung. causing a robotic arm to place a lid on the can. When sensor 1: l/4 in rung 6 detects the placement of the lid. it causes the rung to latch, starting a motor that rotates the table.
Step5: As the table and incremental encoder rotate, the tip-counter C5:0 in rung 8 increments. Alter 72 pulses, the accumulator equals the preset value. The DN output of the counter then sets. causing the corresponding Examine-Off contact in rung 6 to become False. The result is that the rung unlatches and the rotary motor stops.
10 M
5(b)
Draw a block diagram representing Car range management system.
10 M
Write a short note any four Q1.(a,b,c,d,e)
6(a)
Accumulator
5 M
6(b)
Selection of a PLC robot.
5 M
6(c)
Fire fighting robot.
5 M
6(d)
Comb drive
5 M
6(e)
Mechatronics systems in factory and business applications.
5 M
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