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1
Find the octal equivalent of hexadecimal numbers AB.CD
2 M
2
State and prove the consensus theorem.
2 M
3
Implement the function G=Σm(0,3) using a 2×4 decoder.
2 M
4
Draw the circuit for 2-to-1 line multuplexer.
2 M
5
Write the characteristics table and equation of JK flip flop.
2 M
6
Write any two applications of shift register.
2 M
7
Define Race condition.
2 M
8
What are the types of hazards?
2 M
9
What is memory decoding?
2 M
10
Define ASIC.
2 M
Answer any one question from Q11 (a) & Q11 (b)
11 (a)
Simplify the following functions, using K-map techniques
(i) G=ΠM(0, 1, 3, 7, 9, 11)
(ii) f(W,X,Y,Z)=Σm(0, 7, 8, 9, 10, 12)+ Σd(2, 5, 13)
(i) G=ΠM(0, 1, 3, 7, 9, 11)
(ii) f(W,X,Y,Z)=Σm(0, 7, 8, 9, 10, 12)+ Σd(2, 5, 13)
16 M
11 (b)
Minimize the expression using Quine McCluskey (Tabulation) method F=Σm (0,1,9,15,24,29,30)+Σd(8,11,31)
16 M
Answer any one question from Q12 (a) & Q12 (b)
12 (a)
Design a circuit that converts 8421 BCD code to Excess-3 code.
16 M
12 (b)
Implement the following Boolean function using 8 to 1. Multiplexer F(A, B, C, D)= A'BD'+ACD+B'CD+A'C'D. Also implement the function using 16 to 1 multiplexer.
16 M
Answer any one question from Q13 (a) & Q13 (b)
13 (a)
Implement T flip flop using D flip flop and JK flip flop using D flip flop.
16 M
13 (b)
Design a synchronous conunter which counts in the sequence 000, 001, 010, 011, 100, 101, 111, 000 using D-FF.
16 M
Answer any one question from Q14 (a) & Q14 (b)
14 (a)
Explain the steps for the design of asynchronous sequential circuits.
16 M
14 (b)
Implement the switching function F=?m(1,3,5,7,8,9,14,15) by a static hazard free two level AND OR gate network.
16 M
15 (a)
Implement the following function using PLA
A(x,y,z)=Σm(1,2,4,6)
B(x,y,z)=Σm(0,1,6,7)
C(x,y,z)=Σm(2,6)
A(x,y,z)=Σm(1,2,4,6)
B(x,y,z)=Σm(0,1,6,7)
C(x,y,z)=Σm(2,6)
16 M
15 (b)
The following messages have been coded in the even parity Hamming code and transmitted through a noisy channel. Decode the messages, assuming that at most a single error has occurred in each codeword.
(i) 1001001
(ii) 0111001
(iii) 1110110
(iv) 0011011.
(i) 1001001
(ii) 0111001
(iii) 1110110
(iv) 0011011.
16 M
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