# www.stupidsid.com

Most important part of getting into any B-School would be to prepare properly and this section will help you with it. Share your tips and tricks, various helpful links or any plan of action that can help.
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## Tips and Shortcuts 1 year 1 month ago #1

 tasneem OFFLINE Junior Boarder Posts: 33 Thank you received: 16 Karma: 4 Number of Factors: To find the number of factors of a given number, express the number as a product of powers of prime numbers. In this case, 120 can be written as 8 x 3 x 5 = ( 2^3) (3) (5) Now, increment the power of each of the prime numbers by 1 and multiply the result. In this case it will be (3 + 1)*(1 + 1)*(1+1) = 4 * 2 * 2 = 16 (the power of 2 is 3, the power of 3 is 1 and the power of 5 is 1) Therefore, there will 16 factors including 1 and 120. Excluding, these two numbers, you will have 16 – 2 = 14 factors. The administrator has disabled public write access. The following user(s) said Thank You: reena

## Sum on n Natural numbers 1 year 1 month ago #2

 tasneem OFFLINE Junior Boarder Posts: 33 Thank you received: 16 Karma: 4 The sum of first n natural numbers = n (n+1)/2 The sum of squares of first n natural numbers is n (n+1)(2n+1)/6 The sum of first n even numbers= n (n+1) The sum of first n odd numbers= n^2 The administrator has disabled public write access. The following user(s) said Thank You: reena

## Re: Sum on n Natural numbers 1 year 1 month ago #3

 mitesh OFFLINE Senior Boarder Posts: 79 Thank you received: 13 Karma: 3 Some Pythagorean triplets: (easy way to remember them) 3,4,5 (3^2=4+5) 5,12,13 (5^2=12+13) 7,24,25 (7^2=24+25) 8,15,17 (8^2 / 2 = 15+17 ) 9,40,41 (9^2=40+41) 11,60,61 (11^2=60+61) 12,35,37 (12^2 / 2 = 35+37) 16,63,65 (16^2 /2 = 63+65) 20,21,29 (EXCEPTION) The administrator has disabled public write access. The following user(s) said Thank You: reena
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